Power Strings

Time Limit: 3000MS		Memory Limit: 65536K
Total Submissions: 33273		Accepted: 13825

Description

Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = "def" then a*b = "abcdef". If we think of concatenation as multiplication, exponentiation by a non-negative integer is defined in the normal way: a^0 = "" (the empty string) and a^(n+1) = a*(a^n).

Input

Each test case is a line of input representing s, a string of printable characters. The length of s will be at least 1 and will not exceed 1 million characters. A line containing a period follows the last test case.

Output

For each s you should print the largest n such that s = a^n for some string a.

Sample Input

abcdaaaaababab.

Sample Output

143

Hint

This problem has huge input, use scanf instead of cin to avoid time limit exceed.

Source

1 #include
       
         2 #include
        
          3 #include
         
           4 #include
          
            5 using namespace std; 6  7 int next[1000010],m; 8 char s[1000010]; 9 10 void get_next()11 {12     int i=0,j=-1;13     next[0]=-1;14     while(i